The acceleration-time graph for a body is sho | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The velocity-time graph is obtained by integrating the acceleration-time graph,as $v = \int a \, dt$.$1$. From $0$ to $t_{1}$,acceleration $a$ is

Vedclass · Accepted Answer

Vedclass · Answer

(D) The velocity-time graph is obtained by integrating the acceleration-time graph,as $v = \int a \, dt$.$1$. From $0$ to $t_{1}$,acceleration $a$ is constant and positive. Therefore,the velocity increases linearly with time (a straight line with a positive slope).$2$. From $t_{1}$ to $t_{2}$,acceleration $a = 0$. Therefore,the velocity remains constant (a horizontal line).$3$. From $t_{2}$ to $t_{3}$,acceleration $a$ is constant and positive again. Therefore,the velocity increases linearly with time (a straight line with a positive slope).Comparing this behavior with the given options,the graph shown in $823-$d272 correctly represents this motion.

The acceleration-time graph for a body is shown in the graph. Which of the following graphs would probably represent the velocity of the body plotted against time?

Similar Questions

Which of the following position-time $(s-t)$ graphs represents uniform acceleration?

$A$ particle moves along $X$-axis in such a way that its coordinate $x$ varies with time $t$ according to the equation $x = (2 - 5t + 6t^2) \ m$. The initial velocity of the particle is ....... $m/s$.

From the $v-t$ graph,the

The acceleration-time graph for a particle is given. What will be the corresponding velocity-time graph?

For the displacement-time graph shown in the figure,the ratio of the magnitudes of the (constant) speeds during the first two seconds and the next four seconds is

Vedclass Test Series

Exam Paper Generator

Online Exam Module